A simple series circuit carries a current of 3.0 amp when the potential difference across it is 24.0 volts, what is the resistance of this circuit?

To determine the resistance in a simple series circuit, Ohm's Law is employed, which states that the voltage (V) is equal to the current (I) multiplied by the resistance (R). This relationship is expressed in the formula:

[ R = \frac{V}{I} ]

In this scenario, the potential difference (voltage) is given as 24.0 volts, and the current is 3.0 amps. By substituting these values into the formula, we calculate the resistance as follows:

[ R = \frac{24.0 , \text{volts}}{3.0 , \text{amps}} ]

[ R = 8.0 , \text{ohms} ]

This calculation indicates that the resistance in the circuit is 8.0 ohms. Thus, the correct answer is indeed that the resistance of this circuit is 8.0 ohms.

This analysis reinforces the application of Ohm's Law in understanding electrical circuits and highlights the direct relationship between voltage, current, and resistance, which serves as a foundational principle in electronics and physics.